[Uneex] Re: [Uneex] Re: [Uneex] Что позволяет C

[Mike E. Matsnev]

On Mon, Dec 17, 2001 at 11:35:46AM +0300, Peter Novodvorsky wrote:
>     Mike> Даа...  Из K&R: ======= Rather more surprising, at first
>     Mike> sight, is the fact that a reference to a[i] can also be
>     Mike> written as *(a+i). In evaluating a[i], C converts it to
>     Mike> *(a+i) immediately; the two forms are equivalent.  =======
> 
> Однако про i[a] тут ничего сказано не было.
Тут сказано, что для любых X и Y, X[Y] преобразуется в *(X+Y).

/Mike